Optimal. Leaf size=139 \[ -\frac{2 \sin ^2(c+d x) \cos (c+d x)}{5 d \sqrt{a \sin (c+d x)+a}}+\frac{2 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{15 a d}-\frac{28 \cos (c+d x)}{15 d \sqrt{a \sin (c+d x)+a}}+\frac{\sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a \sin (c+d x)+a}}\right )}{\sqrt{a} d} \]
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Rubi [A] time = 0.232121, antiderivative size = 139, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {2778, 2968, 3023, 2751, 2649, 206} \[ -\frac{2 \sin ^2(c+d x) \cos (c+d x)}{5 d \sqrt{a \sin (c+d x)+a}}+\frac{2 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{15 a d}-\frac{28 \cos (c+d x)}{15 d \sqrt{a \sin (c+d x)+a}}+\frac{\sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a \sin (c+d x)+a}}\right )}{\sqrt{a} d} \]
Antiderivative was successfully verified.
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Rule 2778
Rule 2968
Rule 3023
Rule 2751
Rule 2649
Rule 206
Rubi steps
\begin{align*} \int \frac{\sin ^3(c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx &=-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}-\frac{\int \frac{\sin (c+d x) (-4 a+a \sin (c+d x))}{\sqrt{a+a \sin (c+d x)}} \, dx}{5 a}\\ &=-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}-\frac{\int \frac{-4 a \sin (c+d x)+a \sin ^2(c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{5 a}\\ &=-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}+\frac{2 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 a d}-\frac{2 \int \frac{\frac{a^2}{2}-7 a^2 \sin (c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{15 a^2}\\ &=-\frac{28 \cos (c+d x)}{15 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}+\frac{2 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 a d}-\int \frac{1}{\sqrt{a+a \sin (c+d x)}} \, dx\\ &=-\frac{28 \cos (c+d x)}{15 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}+\frac{2 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 a d}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\frac{a \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{d}\\ &=\frac{\sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a+a \sin (c+d x)}}\right )}{\sqrt{a} d}-\frac{28 \cos (c+d x)}{15 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^2(c+d x)}{5 d \sqrt{a+a \sin (c+d x)}}+\frac{2 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 a d}\\ \end{align*}
Mathematica [C] time = 0.233201, size = 150, normalized size = 1.08 \[ \frac{\left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right ) \left (60 \sin \left (\frac{1}{2} (c+d x)\right )+5 \sin \left (\frac{3}{2} (c+d x)\right )-3 \sin \left (\frac{5}{2} (c+d x)\right )-60 \cos \left (\frac{1}{2} (c+d x)\right )+5 \cos \left (\frac{3}{2} (c+d x)\right )+3 \cos \left (\frac{5}{2} (c+d x)\right )+(-60-60 i) (-1)^{3/4} \tanh ^{-1}\left (\left (\frac{1}{2}+\frac{i}{2}\right ) (-1)^{3/4} \left (\tan \left (\frac{1}{4} (c+d x)\right )-1\right )\right )\right )}{30 d \sqrt{a (\sin (c+d x)+1)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.589, size = 130, normalized size = 0.9 \begin{align*}{\frac{1+\sin \left ( dx+c \right ) }{15\,{a}^{3}\cos \left ( dx+c \right ) d}\sqrt{-a \left ( \sin \left ( dx+c \right ) -1 \right ) } \left ( 15\,{a}^{5/2}\sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{a-a\sin \left ( dx+c \right ) }\sqrt{2}}{\sqrt{a}}} \right ) -6\, \left ( a-a\sin \left ( dx+c \right ) \right ) ^{5/2}+10\, \left ( a-a\sin \left ( dx+c \right ) \right ) ^{3/2}a-30\,{a}^{2}\sqrt{a-a\sin \left ( dx+c \right ) } \right ){\frac{1}{\sqrt{a+a\sin \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (d x + c\right )^{3}}{\sqrt{a \sin \left (d x + c\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.90647, size = 648, normalized size = 4.66 \begin{align*} \frac{\frac{15 \, \sqrt{2}{\left (a \cos \left (d x + c\right ) + a \sin \left (d x + c\right ) + a\right )} \log \left (-\frac{\cos \left (d x + c\right )^{2} -{\left (\cos \left (d x + c\right ) - 2\right )} \sin \left (d x + c\right ) + \frac{2 \, \sqrt{2} \sqrt{a \sin \left (d x + c\right ) + a}{\left (\cos \left (d x + c\right ) - \sin \left (d x + c\right ) + 1\right )}}{\sqrt{a}} + 3 \, \cos \left (d x + c\right ) + 2}{\cos \left (d x + c\right )^{2} -{\left (\cos \left (d x + c\right ) + 2\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 2}\right )}{\sqrt{a}} + 4 \,{\left (3 \, \cos \left (d x + c\right )^{3} + 4 \, \cos \left (d x + c\right )^{2} -{\left (3 \, \cos \left (d x + c\right )^{2} - \cos \left (d x + c\right ) - 17\right )} \sin \left (d x + c\right ) - 16 \, \cos \left (d x + c\right ) - 17\right )} \sqrt{a \sin \left (d x + c\right ) + a}}{30 \,{\left (a d \cos \left (d x + c\right ) + a d \sin \left (d x + c\right ) + a d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 3.41578, size = 410, normalized size = 2.95 \begin{align*} -\frac{\frac{120 \, \sqrt{2} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \sqrt{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} + \sqrt{a}\right )}}{2 \, \sqrt{-a}}\right )}{\sqrt{-a} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )} - \frac{{\left ({\left ({\left ({\left (\frac{13 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right ) \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{7}} - \frac{15 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{a^{7}}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \frac{40 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{a^{7}}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \frac{40 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{a^{7}}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \frac{15 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{a^{7}}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \frac{13 \, \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{a^{7}}}{{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a\right )}^{\frac{5}{2}}} - \frac{{\left (120 \, \sqrt{2} a^{\frac{21}{2}} \arctan \left (\frac{\sqrt{a}}{\sqrt{-a}}\right ) + 17 \, \sqrt{2} \sqrt{-a} a\right )} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{\sqrt{-a} a^{\frac{21}{2}}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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